-16x^2+48x+1053=0

Solution for -16x^2+48x+1053=0 equation:

-16x^2+48x+1053=0

a = -16; b = 48; c = +1053;
Δ = b2-4ac
Δ = 482-4·(-16)·1053
Δ = 69696
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{69696}=264$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-264}{2*-16}=\frac{-312}{-32}
=9+3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+264}{2*-16}=\frac{216}{-32}
=-6+3/4
$